Question

$A \: body \: projected \: upward \: is \: a t \: the \: same \\ \: height \: from \: ground \: at \: t = 1s \: and \\ t = 9s. \: find \: the \: maximum \: height \: attained \: by \: it \: \\ (take\: g = \: \frac{10m}{ {s}^{2} } )$
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Answer 1

${\huge {\mathfrak {Answer :-}}}$

Refer above in the attachment. ⬆️ ⬆️

Key points :-

• At the maximum height, the velocity of the body becomes 0.
• v^2 = u^2 - 2gh
• s = ut - 1/2 * gt^2

➡️ Hence, the maximum height attained by the body is 80 metres.

Thanks..