Question

$a \ + \frac{1}{a} = 2 \: find \: {a}^{2} \ + \frac{1}{ {a}^{2} }$
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Answer 1

Answer: 2

Step-by-step explanation:

$a + \frac{1}{a} =2$

$(a + \frac{1}{a})^2 = 2^2$

$a^2 + 2 *a * \frac{1}{a}  + \frac{1}{a^2} = 4$

In 2 * a * 1/a , the a and 1/a cancels out . So we are left with only 2

∴ $a^2 + 2 + \frac{1}{a^2} = 4$

⇒ $a^2 + \frac{1}{a^2} = 2$

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