Physics, asked by prathik19, 9 months ago

A \:man\: weighing \:600 N\: carries\: a \:load \:of\: 200 N\: on \:his\: head. \:If \:he\: climbs \:a\: height\: of \:5m \:then\: Find\: the\: work\: done.}

Answers

Answered by Anonymous
23

\huge\sf\underline\red{Given:-}

  • \textsf { Man weighting 600N carries a load  }

\:\:\:\:\:\:\:\:\:\:\:\textsf{of 200N on his head}

\\

\huge\sf\underline\orange{To\:Find:-}

  • \textsf{Find the work done if the person  }

\:\:\:\:\:\:\:\:\:\:\textsf{climbs height of 5m}

\\

\huge\sf\underline\blue{Figure:-}

 \setlength{\unitlength}{1.9mm}\begin{picture}(30,20)\linethickness{5 mm}\multiput(0,0)(5,3.1){7}{\line(1,0){5}}\linethickness{3 mm}\put(35.5,17){\line(0,1){25}}\linethickness{0.2 mm}\put(-6.75,-4){\line(0,1){44}}\put(0,-1.5){\line(-1,0){7}}\linethickness{6 mm}\put(-7,-4){\line(1,0){43}}\put(-7,40){\line(1,0){43}}\put(34,28){\circle*{1.5}}\linethickness{2 mm}\put(2,2){\line(0,1){5}}\qbezier(-0.8,9)(-1,9)(1.5,7)\qbezier(-2.3,8)(-2.4,6)(-2.5,4)\qbezier(-2.5,4)(-2.8,2)(-3.2,0)\linethickness{4 mm}\put(-1.6,8){\line(0,1){2}}\put(-1.5,18.5){\circle*{4}}\linethickness{1.5 mm}\qbezier(-1.7,15)(-4.1,12)(-4.1,12)\put(-4.1,12){\line(0,-1){3}}\qbezier(0,15)(1.5,12)(1.5,12)\qbezier(1.5,12)(3,11.8)(4,11.6)\linethickness{0.2mm}\put(-2.95,10){\dashbox{0.1}(2.6,6)[l]}\end{picture}

\\

\huge\sf\underline\purple{Solution:-}

\mapsto\:\sf\orange{Weight\: of\: the\: man \:=\: 600 N}

\mapsto\:\sf\blue{Weight \:of\: the\: load \:=\: 200 N}

\mapsto\:\sf\green{Total \:weight\: =\: (600+200) N \:=\: 800 N}

\star\:\:\sf\red{Now , \:Work \:done\: =\: (weight \times height)}

\hookrightarrow\:\sf\orange{Work \:done\: =\: (800 \times 5)\:Joules}

\hookrightarrow\:{\boxed{\sf{\pink{Work done =\:4,000\:Joules}}}}

Similar questions