Math, asked by vedantbhangale, 18 hours ago


(ab + bc + ac) {}^{2} = ac(a + b + c) {}^{2}

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Answers

Answered by LEAERNforFUN
0

Answer:

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Step-by-step explanation:

I am assuming that by AC you mean ac.

Substitute same numbers for a, b , and c ( positive or negative) left hand side of the equation will be equal to zero I.e. the right hand side.

Example:

substitute 4 for a, b and c

4^2+4^2+4^2–4*4–4*4–4*4 = 16+16+16–16–16–16 = 0

or substitute -5 for a, b and c

(-5)^2 + (-5)^2 + (-5)^2 - (-5)*(-5) - (-5)*(-5) - (-5)*(-5) = 25+25+25-25–25–25 = 75–75 = 0

This will work for any numbers as long as

a = b = c

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