Question

$algebra \: \: exercise$
$1.9x - (2x - 5)$
$2. ({9x}^2{ - 16x - 4} ) - ( {15x - 12x}^2 \: + {5)}$

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Answer 1

$\huge\mathcal\colorbox{lime}{ᴀɴSᴡᴇʀ~~~↓}$

$\bf(1) \: 9x - (2x - 5) \\ \bf 9x - 2x + 5 \\ \bf {\underline{\underline{7x + 5}}}$

$\bf(2) \:( {9x}^{2} - 16x - 4) - (15x - {12x}^{2} + 5) \\ \bf {9x}^{2} - 16x - 4 - 15x + {12x}^{2} - 5 \\ \bf \underline{ \underline{{21x}^{2} - 31x - 9}}$

$\huge\sf\green{ʜᴏᴘᴇ~ɪᴛ~ʜᴇʟᴘs..!!}$

Answer 2

$\bf\huge\underline\blue{Answer}$

$9x - (2x - 5) \\ 9x - 2x + 5 \\ 7x + 5$

$9 {x}^{2} - 16x - 4 - (15x - 12 {x}^{2} + 5) \\ 9 {x}^{2} - 16x - 4 - 15x + 12 {x}^{2} - 5 \\ 9 {x}^{2} + 12 {x}^{2} - 16x - 15x - 4 - 5 \\ 21 {x}^{2} - 31x - 9$