Question

$aloha$
Find the factors:

=>
$2 {k}^{2} + 5k + 3$


$thanks$

Answer 1

Hey dear !!

Here is your answer !!

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♦♦ Given ->2k^2+5k+3

♦♦ Solution ->

2k^2+2k+3k+3=0

2k(k+1) +3(k+1)=0

2k+3=0, k+1=0

2k=-3 , k=-1

k=-3/2 , k=-1

Hence -3/2 and -1 are the zeroes

Hope it is satisfactory :-)
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Answer 2

$2 {k}^{2} + 5k + 3 \\ = 2 {k }^{2} + 2k + 3k + 3 \\ = 2k(k + 1) + 3(k + 1) \\ = (2k + 3)(k + 1)$
Therefore, Factors are (2k+3) and (k+1)