Question

$\alpha = - 3 2 \beta = - 1$
If -3/2,1 are the Zero of the Polynomial.​

Answer 1

Answer:

= k ($x^2$-(∝ + β)$x$ + β)

= ∝ + β = -3/2 + (-1)

= -3/2 + (-1)

= -3 -2/2

= ∝ + β = 5/2

= ∝β = (-3/2) (-1)

= ∝β = (3/2)

= k ($x^2$ - (∝ + β)$x$ + ∝β)

= k($x^2$ - (-5/2)$x$ + 3/2)

= k (2$x^3$ + 5$x$ + 3)/2

= k =2, p($x$) = (2$x^2$ + 5$x$ + 3)