![\alpha \: and \: \beta \: are \: zeroes \: of \: the \: quadratic \: polym \\ nomial \: x {}^{2} - (k \: + 6)x + 2(2k - 1).find \: the \: value \: of \: k \: if \: \alpha + \beta = \frac{1}{2 } \alpha \beta \alpha \: and \: \beta \: are \: zeroes \: of \: the \: quadratic \: polym \\ nomial \: x {}^{2} - (k \: + 6)x + 2(2k - 1).find \: the \: value \: of \: k \: if \: \alpha + \beta = \frac{1}{2 } \alpha \beta](https://tex.z-dn.net/?f=+%5Calpha+%5C%3A+++and+%5C%3A++%5Cbeta++%5C%3A+are+%5C%3A+zeroes+%5C%3A+of+%5C%3A+the+%5C%3A+quadratic+%5C%3A+polym+%5C%5C+nomial+%5C%3A+x+%7B%7D%5E%7B2%7D++-+%28k+%5C%3A++%2B+6%29x+%2B+2%282k+-+1%29.find+%5C%3A+the+%5C%3A+value+%5C%3A+of+%5C%3A+k+%5C%3A+if+%5C%3A++%5Calpha++%2B++%5Cbeta++%3D++%5Cfrac%7B1%7D%7B2+%7D++%5Calpha++%5Cbeta+)
please solve this on a paper .........plz
Answers
Answered by
4
Hola User_____________
Here is Your Answer...!!!..
______________________
☆Actually welcome to the concept of the quadratic equations....
☆Basically the given equation has the complex roots or the unreal roots ...thus the value of k is a complex number....
_______________________
Hope it helps u....☺
Here is Your Answer...!!!..
______________________
☆Actually welcome to the concept of the quadratic equations....
☆Basically the given equation has the complex roots or the unreal roots ...thus the value of k is a complex number....
_______________________
Hope it helps u....☺
Attachments:
![](https://hi-static.z-dn.net/files/dcc/ec9cae34dfac6c1002da809a03126809.jpg)
![](https://hi-static.z-dn.net/files/da9/312a9fdd1074e96f427fe92167630d3f.jpg)
Anonymous:
Thnx
Similar questions
Social Sciences,
8 months ago
India Languages,
8 months ago
Hindi,
1 year ago
Accountancy,
1 year ago
Chemistry,
1 year ago