Question

$\alpha + \beta = 3 \\ \alpha \beta = 7 \\ then \: form \: a \: quadritic \: equation$
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Answer 1

Answer:

soz=3

poz=7

quadratic equation

${x}^{2} - 3x + 7$

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Answer 2

Answer:

Quadratic equation is

x^2 -(sum of zeroes )x + product of zeroes =0

and its proportional has roots

here alpha and beta are roots

So, quadratic equation becomes

x^2-(alpha + beta)x + alpha beta =0

x^2 -3x +7=0

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