Math, asked by mukheshms2005, 3 months ago

\alpha \beta \geq \geq \geq x^{2} \left \{ {{y=2} \atop {x=2}} \right. \left \{ {{y=2} \atop {x=2}} \right. x^{2} \sqrt{x} \sqrt[n]{x} \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]

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Answered by sharmaprakriti1312
0

Answer:

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Answered by kg150512
2

Answer:

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