Question

$answer \: this \: question \: with \: solution \\ steps.$
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Answer 1

Answer:

(4/7)^2x.(4/7)^5.(4/7)^-2=(4/7)^3÷(4/7)^-x

=> (4/7)^(2x+5-2)=(4/7)^{3-(-x)}

=> (4/7)^(2x+3)=(4/7)^(3+x)

=> 2x+3=3+x

=> 2x-x=3-3

=> x=0

Answer 2

Answer:

$Hope \: it \: helps!$

$x \: = \: 0$