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A vertical pole of a length 6 m casts a shadow 4m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower ??
Answers
Answered by
7
Answer:
Height of pole=AB=6 m
Length of shadow of pole =BC=4 m
Length of shadow of tower=EF=28 m
In △ABC and △DEF
∠B=∠E=90° both 90°as both are vertical to ground
∠C=∠F (same elevation in both the cases as both shadows are cast at the same time)
∴△ABC∼△DEF by AA similarity criterion
We know that if two triangles are similar, ratio of their sides are in proportion
⇒DE=6×7=42 m
Hence the height of the tower is 42 m
Answered by
7
Answer:
Step-by-step explanation:
Answer:
Height of pole=AB=6 m
Length of shadow of pole =BC=4 m
Length of shadow of tower=EF=28 m
In △ABC and △DEF
∠B=∠E=90° both 90°as both are vertical to ground
∠C=∠F (same elevation in both the cases as both shadows are cast at the same time)
∴△ABC∼△DEF by AA similarity criterion
We know that if two triangles are similar, ratio of their sides are in proportion
\begin{gathered}so \: \: \: \frac{ab}{de} = \frac{bc}{ef} \\ \end{gathered}
so
de
ab
=
ef
bc
\begin{gathered} \frac{6}{de} = \frac{4}{28} \\ \end{gathered}
de
6
=
28
4
⇒DE=6×7=42 m
Hence the height of the tower is 42 m
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