Math, asked by Renumahala2601, 1 month ago


★ ANY MODERATORS ★\  \textless \ br /\  \textgreater \ \  \textless \ br /\  \textgreater \ ⍟ STARS ⍟\  \textless \ br /\  \textgreater \ \  \textless \ br /\  \textgreater \ ᯽ OTHER BEST USERS ᯽ \  \textless \ br /\  \textgreater \ \  \textless \ br /\  \textgreater \ ︎︎⚠︎ NO SPAM ⚠︎︎︎︎\  \textless \ br /\  \textgreater \ \  \textless \ br /\  \textgreater \ ♲︎︎︎ OTHERWISE REPORTED AND DELETED ♲︎​\  \textless \ br /\  \textgreater \ \  \textless \ br /\  \textgreater \ \  \textless \ br /\  \textgreater \ \  \textless \ br /\  \textgreater \ \sf \huge \: question : -question:− \  \textless \ br /\  \textgreater \ \  \textless \ br /\  \textgreater \ \  \textless \ br /\  \textgreater \ \  \textless \ br /\  \textgreater \ A vertical pole of a length 6 m casts a shadow 4m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower ?? ​
★ ANY MODERATORS ★

⍟ STARS ⍟

᯽ OTHER BEST USERS ᯽

︎︎⚠︎ NO SPAM ⚠︎︎︎︎

♲︎︎︎ OTHERWISE REPORTED AND DELETED ♲︎​



\sf \huge \: question : - question:−



A vertical pole of a length 6 m casts a shadow 4m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower ?? ​​

Answers

Answered by MrNishhh
7

Answer:

Height of pole=AB=6 m

Length of shadow of pole =BC=4 m

Length of shadow of tower=EF=28 m

In △ABC and △DEF

∠B=∠E=90° both 90°as both are vertical to ground

∠C=∠F (same elevation in both the cases as both shadows are cast at the same time)

∴△ABC∼△DEF by AA similarity criterion

We know that if two triangles are similar, ratio of their sides are in proportion

so, \:  \:  \:  \frac{AB}{DE}  =  \frac{BC}{EF}  \\

 \frac{6}{DE}  =  \frac{4}{28}  \\

⇒DE=6×7=42 m

Hence the height of the tower is 42 m

Answered by technogamerzof098
7

Answer:

Answer:</p><p></p><p>Height of pole=AB=6 m</p><p></p><p>Length of shadow of pole =BC=4 m</p><p></p><p>Length of shadow of tower=EF=28 m</p><p></p><p>In △ABC and △DEF</p><p></p><p>∠B=∠E=90° both 90°as both are vertical to ground</p><p></p><p>∠C=∠F (same elevation in both the cases as both shadows are cast at the same time)</p><p></p><p>∴△ABC∼△DEF by AA similarity criterion</p><p></p><p>We know that if two triangles are similar, ratio of their sides are in proportion</p><p></p><p>\begin{gathered}so \: \: \: \frac{ab}{de} = \frac{bc}{ef} \\ \end{gathered}sodeab=efbc</p><p></p><p>\begin{gathered} \frac{6}{de} = \frac{4}{28} \\ \end{gathered}de6=284</p><p></p><p>⇒DE=6×7=42 m</p><p></p><p>Hence the height of the tower is 42 m</p><p></p><p>

Step-by-step explanation:

Answer:

Height of pole=AB=6 m

Length of shadow of pole =BC=4 m

Length of shadow of tower=EF=28 m

In △ABC and △DEF

∠B=∠E=90° both 90°as both are vertical to ground

∠C=∠F (same elevation in both the cases as both shadows are cast at the same time)

∴△ABC∼△DEF by AA similarity criterion

We know that if two triangles are similar, ratio of their sides are in proportion

\begin{gathered}so \: \: \: \frac{ab}{de} = \frac{bc}{ef} \\ \end{gathered}

so

de

ab

=

ef

bc

\begin{gathered} \frac{6}{de} = \frac{4}{28} \\ \end{gathered}

de

6

=

28

4

⇒DE=6×7=42 m

Hence the height of the tower is 42 m

Similar questions