Science, asked by thapaavinitika6765, 7 months ago

area\:f\left(x\right)=\sin \left(x\right),\:0,\:2\pi

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Answers

Answered by hiteshnagrota1977
2

Answer:

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Answered by Anonymous
2

\mathrm{Area\:under\:the\:curve}\:f\left(x\right)=\sin \left(x\right)\:\mathrm{on\:interval}\:\left[0,\:2\pi \right]:\quad 4

A=\int _a^b|f\left(x\right)|dx

\mathrm{Apply\:the\:area\:formula}:\quad \int _0^{2\pi }\left|\sin \left(x\right)\right|dx

\mathrm{Solve\:}\:\int _0^{2\pi }\left|\sin \left(x\right)\right|dx:\quad 4

\mathrm{The\:area\:is:}

4

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