Question

$Arrange the following fraction in descending order;\\\\\frac{2}{3},\frac{3}{5}, \frac{7}{10}, \frac{8}{15}$

Answer 1

Answer:

LCM of 3, 5, 10 and 15=3 × 5 × 2=30

Now , let us change each of the given fraction into an equivalent fraction having 30 as the denominator.

[(2/3) × (10/10)] = (20/30)

[(3/5) × (6/6)] = (18/30)

[(7/10) × (3/3)] = (21/30)

[(8/15) × (2/2)] = (16/30)  

Clearly,

(21/30) > (20/30) > (18/30) > (16/30)

Hence,

(7/10) > (2/3) > (3/5) > (8/15)

Hence,the given fractions in descending order are (7/10), (2/3), (3/5), (8/15)

Hope it helps you!!

Answer 2

$find \: the \: lcm \: = \ \: 3 \: 5 \: 10 \: 15 \: = 30 \\ \\ \frac{2 \times 10}{3 \times 10} = \frac{20}{30} \\ \frac{3 \times 6}{5 \times 6} = \frac{18}{30} \\ \frac{7 \times 3}{10 \times 3 } = \frac{21}{30} \\ \frac{8 \times 2}{15 \times 2} = \frac{16}{30} \\ \\ \frac{21}{30} > \frac{20}{30} > \frac{18}{30} > \frac{16}{30} \\ = \frac{7}{10} > \frac{2}{3} > \frac{3}{5} > \frac{8}{15}$