Question

$\) As given (5x²+14x+2)²−(4x²−5x+7)² is divided by x²+x+1 <=((5x²+14x−5)−(4x²−5x+7))((5x²+14x+2)+(4x²−5x+7)) =(5x²+14x+2−4x²+5x−7)(5x²+14x+2+4x²−5x+7) <=(x²+19x−5)(9x²+9x+9) =(x²+19x−5)9(x²+x+1) Now dividing by x²+x+1 \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \frac{x2+x+1}{(x2+19x−5)9(x2+x+1)} (x2+19x−5)9(x2+x+1)x2+x+1\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ Quotient=9(x2+19x−5)andReminder=0\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater$
If you like my answer, please mark it as ✔️BRAINLIEST! Good Luck and have a nice day!! :)​

Answer 1

Answer:

As given (5x

2

+14x+2)

2

−(4x

2

−5x+7)

2

is divided by x

2

+x+1

=((5x

2

+14x−5)−(4x

2

−5x+7))((5x

2

+14x+2)+(4x

2

−5x+7))

=(5x

2

+14x+2−4x

2

+5x−7)(5x

2

+14x+2+4x

2

−5x+7)

=(x

2

+19x−5)(9x

2

+9x+9)

=(x

2

+19x−5)9(x

2

+x+1)

Now dividing by x

2

+x+1

=

x

2

+x+1

(x

2

+19x−5)9(x

2

+x+1)

Quotient=9(x

2

+19x−5)andReminder=0

Explanation:

PLS MARK AS BRAINLIEST

Answer 2

Answer:

Quotient=9(x

2

+19x−5)andReminder=0

Explanation:

verified

Verified by Toppr

Correct option is B)

As given (5x

2

+14x+2)

2

−(4x

2

−5x+7)

2

is divided by x

2

+x+1

=((5x

2

+14x−5)−(4x

2

−5x+7))((5x

2

+14x+2)+(4x

2

−5x+7))

=(5x

2

+14x+2−4x

2

+5x−7)(5x

2

+14x+2+4x

2

−5x+7)

=(x

2

+19x−5)(9x

2

+9x+9)

=(x

2

+19x−5)9(x

2

+x+1)

Now dividing by x

2

+x+1

=

x

2

+x+1

(x

2

+19x−5)9(x

2

+x+1)

Quotient=9(x

2

+19x−5)andReminder=0