Question

$ax + by = c \\ bx + ay = 1 + c \\ \\ find \: the \: value \: of \: x \: and \: y$
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Answer 1

Sol :

Given equations are ax+by = c --------------(1) and ay+bx = c+1 --------------(2)

multiply equation (1) by 'b' and equation (2) by 'a' we get

abx+b2y = bc

abx +a2y= ac+a (substract)

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( b2-a2)y = bc - ac -a

y = (bc - ac -a) / ( b2-a2)

multiply equation (1) by 'a' and equation (2) by 'b' we get

a2x+aby = ac

aby+b2x = bc+b (substract)

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(a2- b2)x = (ac-bc -b)

x = (ac-bc -b) / (a2- b2)

∴ the values of x and y are (ac-bc -b) / (a2- b2) , (bc - ac -a) / ( b2-a2)

3.2

or↑↑↑.

First add the equations

ax+by+bx+ay=c+1+cx(a+b)+y(a+b)=1+2c(a+b)(x+y)=1+2cx+y=1+2c/(a+b)

now subtractax

-bx+by-ay=c-1+cx(a-b)+y(a-b)=1x+y=1/(a-b)

now solve

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Answer 2

Answer:

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