Question

${b }^{2} + 8b + 16 \: by \: b + 4$
​

Answer 1

Step-by-step explanation:

$b {}^{2} + 8b + 16 \div b + 4$

${b}^{2} + 8b + \frac{16}{b} + 4$

$\frac{b {}^{3 \times} + 8 {b}^{2} + 16 + 4b}{b}$

please Marked me as brainly