Question

$b(n) = 1 \left(-2\right)^{n - 1}$
What is the 4th term in the sequence?

Answer 1

Answer:

b(n) = 1(-2)^n-1

Now n = 4,

$b(4) \: = \: 1 {( - 2)}^{4 - 1}$

$b(4) = 1 {( - 2)}^{3}$

$b(4) = 1( - 8)$

$b(4) = - 8$

Answer 2

b(n) = 1(-2)^n-1

b(n) = 1(-2)^n-1Now n = 4,

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