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Step-by-step explanation:
Solve for x: a.(2−x)(x+3)⩾0a.(2−x)(x+3)⩾0 b.(x−1)2<0b.(x−1)
2
<0 c.(2x+1)(3−x)>0c.(2x+1)(3−x)>0 d.x2⩾xd.x
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⩾x e.x2⩾3xe.x
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⩾3x f.3x2+2x<0f.3x
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+2x<0 g.x2<4g.x
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<4 h.2x2⩾4h.2x
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⩾4 i.x2+4x+4>0i.x
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+4x+4>0 j.2x2⩾x+3j.2x
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⩾x+3 k.4x2−4x+1<0k.4x
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−4x+1<0 l.6x2+7x<3l.6x
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+7x<3 m.3x2>8(x+2)m.3x
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>8(x+2) n.2x2−4x+2>0n.2x
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−4x+2>0 o.6x2+1⩽5xo.6x
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+1⩽5x p.1+5x<6x2p.1+5x<6x
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q.12x2⩾5x+2q.12x
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⩾5x+2 r.2x2+9>9xr.2x
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+9>9x
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