Question

$\begin{cases}a(1)=20\\\\ a(n)=a(n-1)\cdot\dfrac32 \end{cases}$
what is the 3rd term in the sequence?

Answer 1

Answer:

tex]\begin{cases}a(1)=20\\\\ a(n)=a(n-1)\cdot\dfrac32 \end{cases}[/tex]

what is the 3rd term in the sequence?

Answer 2

Hey Mate!!

Given ;

a(1) = 20

a(n) = a(n-1) . 3/2

So, a = 20

3rd term ;

a(3) = 20(3-1) ×3/2

a(3) = 20×(2) × 3/2

a(3) = 20×3

a(3) = 60

So, a(3) = 60

Hope this helps you!!