![\begin{cases}b(1)=-500\\\\ b(n)=b(n-1)\cdot \dfrac{4}{5} \end{cases} \begin{cases}b(1)=-500\\\\ b(n)=b(n-1)\cdot \dfrac{4}{5} \end{cases}](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7Db%281%29%3D-500%5C%5C%5C%5C+b%28n%29%3Db%28n-1%29%5Ccdot+%5Cdfrac%7B4%7D%7B5%7D+%5Cend%7Bcases%7D)
What is the 3rd term in the sequence?
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Answer:
b(1) = -500
b(2) = b(2-1).4/5 = b(1).4/5 = -500×4/5 = -400
b(3) = b(3-1).4/5 = b(2).4/5 = -400×4/5 = -320
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