Question

$\begin{cases}d(1)=\dfrac{1}{12}\\\\ d(n)=d(n-1)\cdot (-6) \end$
what is the 4th term in the sequence

Answer 1

$\huge\underline\bold\blue{Answer}$

In the sequence 2, 4, 6, 8, 10... there is an obvious pattern. Such sequences can be expressed in terms of the nth term of the sequence. ... To find the 1st term, put n = 1 into the formula, to find the 4th term, replace the n's by 4's: 4th term = 2 × 4 = 8.

Answer 2

Step-by-step explanation:

In the sequence 2, 4, 6, 8, 10... there is an obvious pattern. Such sequences can be expressed in terms of the nth term of the sequence. ... To find the 1st term, put n = 1 into the formula, to find the 4th term, replace the n's by 4's: 4th term = 2 × 4 = 8.