Question

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If p,q are the roots of ax² - bx + c = 0 ( a ≠ 0 ), then p + q is

Answer 1

We have here a quadratic equation. When we find the roots of an equation such as this, we use the quadratic formula:

$\rm x = (-b ± √(b2 - 4ac)) / 2a$

where a, b, and c are coefficients.

In this equation

• a = a
• b = -b
• c = c

The plus/minus sign indicates that we will have two solutions. Suppose that root p was found using the plus and root q was found using the minus. We will have these roots.

$\rm p = (b + √(b² - 4ac)) / 2a$

and

$\rm q = (b - √(b² - 4ac)) / 2a$

Since we want to find the value of p+q, we simply add the formula.

$\rm p + q = ((b + √(b2² - 4ac))+(b - √(b² - 4ac)))/2a$

The square-root terms cancel each other out.

$\rm p + q = 2b / 2a$

$\rm + q = b / a$

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hope this Will help you!!

Answer 2

Answer:

main ans will be q=b/a

hope it help you

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