Question

$\begin{gathered} \huge \circ + \circ = 10 \\ \huge\circ \times \square + \square = 12 \\ \huge \circ \times \square - \triangle \times \circ = \circ \\ \huge \triangle = ?\end{gathered}$



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Answer 1

Answer:

your solution is as follows

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Step-by-step explanation:

$to \: find : \\ value \: of \: symbol \: △ \\ \\ so \: here \\ \: since \: all \: the \: shapes \: \\ are \: of \: same \: size \: ie \: ar e\: identical \\ \\ let \: then \\ ∘ = x \\ □ = y \\ △ = z$

$so \: according \: to \: first \: condition \\ x + x = 10 \\ \\ 2x = 10 \\ \\ x = 5 \\ \\ according \: to \: second \: condition \\ \\ x(y + y) = 12 \\ \\ 2xy = 12 \\ \\ xy = 6 \\ \\ y = \frac{6}{x} \\ \\y = \frac{6}{5}$

$according \: to \: third \: condition \\ \\ xy - xz = x \\ \\ x(y - z) = x \\ \\ y - z = 1 \\ \\ z = y - 1 \\ \\ = \frac{6}{5} - 1 \\ \\ = \frac{6 - 5}{5} \\ \\ z= \frac{1}{5} \\ \\ hence \: \: then \\ \\ △ = \frac{1}{5}$