Question

$\bf{Evaluate\: the\: determinant:-}$
$\left|\begin{array}{ccc}3&-1&-2\\0&0&-1\\3&-5&0\end{array}\right|$

Answer 1

$\bigstar \: \boxed{\sf{\color{purple}{Question:}}}$

$\bf{Evaluate\: the\: determinant:-}$

$\left|\begin{array}{ccc}3&-1&-2\\0&0&-1\\3&-5&0\end{array}\right|$

$\bigstar \: \boxed{\sf{\color{purple}{ Verified Answer:}}}$

(i) = (cos θ)(cos θ) − (−sin θ)(sin θ) = cos2 θ+ sin2 θ = 1

(ii) = (x2 − x + 1)(x + 1) − (x − 1)(x + 1)

= x3 − x2 + x + x2 − x + 1 − (x2 − 1)

= x3 + 1 − x2 + 1

= x3 − x2 + 2

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Answer 2

Answer:

Here is your answer miss,

Step-by-step explanation:

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