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Answers
Step-by-step explanation:
Question:-
Ten years ago the ratio of the ages of Ramesh and Suresh was 1: 5 . Ten years hence the ratio of their ages will be 3 : 5 then,
Find the present age of Ramesh.
How old was Suresh ten years ago?
Solution:-
Let the present age of Ramesh be x
And the present age of Suresh be y
Ten years ago:-
Age of Ramesh = x - 10
Age of Suresh = y - 10
The ratio of the ages of their was 1:5
Ten years later:-
Age of Ramesh = x + 10
Age of Suresh = y + 10
The ratio of their ages will be 3 : 5
Equation (i) - (ii):-
Substitute y = 30 in equation (i):-
Age of Suresh 10 years ago:-
= y - 10
= 30 - 10 = 20 years
Ten years ago Ramesh Age : Suresh Age
1 : 5
10 years later, 3 : 5
Let the present ratio x : y
Ten years ago ratio x - 10 : y - 10
Ten years later ratio x + 10 : y + 10
Compare ratio of ten years ago
5x - 50 = y - 10
5x - y = 40 ------> Eq. 1
Compare ratio of ten years later
5x + 50 = 3y + 30
5x - 3y = - 20 --------> Eq. 2
Solve equation 1 & 2, substitute 2 from 1
(5x - y) - (5x - 3y) = 40 - ( - 20)
2y = 60
5x = 40 + 30
a) Present age of Ramesh = x
= 14 years
b) Suresh age ten years ago = y - 10
= 30 - 10
= 20 years