In a rhombus ABCD show that diagonal AC bisects ∠A as well as ∠C and diagonal BD bisects ∠B as well as ∠D.
Answers
Answer:
Inrhombusallsideareequalanddiagonolsaredifferentbutintersectat90
⇒AB=BC=CD=DA
⇒AC⊥BD
InΔABC
⇒AB=BC
⇒∴∠CAB=∠ACB
⇒AO=OC
∴∠ABO=∠CBO
andsimillarlyinΔADC
⇒AD=DC
⇒AO=OC
∴correspondingangleareequal
⇒∠DAC=∠DCA
and∠CDO=∠ADO
Hence,AC bisect ∠Aand∠C and BD bisects ∠Band∠D
Step-by-step explanation:
Hope this helps
Question :-
In a rhombus ABCD show that diagonal AC bisects ∠A as well as ∠C and diagonal BD bisects ∠B as well as ∠D.
To Prove :-
diagonal AC bisects ∠A as well as ∠C and diagonal BD bisects ∠B as well as ∠D
Construction :-
- Join A and C
- Join B and D
Proof :-
In rhombus all sides are equal
so, AB = BC = CD = DA
In △ABC and △ADC
AB = DA
BC = CD
AC = AC
△ABC ≅ △ADC [ By SSS congruence rule]
∠BAC = ∠DAC [ By CPCT ]
∠BCA = ∠DCA [ By CPCT ]
So, AC bisects ∠A as well as ∠C.
In △DAB and △DCB
DA = CD
AB = BC
BD = BD
△DAB ≅ △DCB [ By SSS congruence rule]
∠ADB = ∠CDB [ By CPCT ]
∠ABD = ∠CBD [ By CPCT ]
So, BD bisects ∠B as well as ∠D.
Additionally✏
- SSS congruence rule - If three sides of one triangle are equal to three sides of another triangle, then the triangles are congruent.
- SAS congruence rule - If two sides and the included angle of one triangle are equal to two sides and included angle of another triangle, then the triangles are congruent.
- ASA congruence rule - If two angles and the included side of one triangle are equal to two angles and included side of another triangle, then the triangles are congruent.
- AAS congruence rule - If two angles and a non-included side of one triangle are equal to two angles and a non-included side of another triangle, then the triangles are congruent.
- RHS congruence rule - If the hypotenuse and one leg of one right-angled triangle are equal to the corresponding hypotenuse and leg of another right-angled triangle, the two triangles are congruent.
- CPCT stands for corresponding parts of congruent triangle.