Question

${\bf{\pmb{\color{red}{Question :-}}}}$
Express $\sf{4^{-3}}$ as a power with the base 2.​

Answer 1

Express $\sf{4^{-3}}$ as a power with the base 2.

We have,

4 = 2 × 2 = 2²

Therefore,

$\sf{(4)^{-3}}$ = $\sf{(2 × 2)^{-3}}$ = (2²$\sf{)^{-3}}$

= $\sf{2^{2 × (-3)}}$

= $\sf{2^{-6}}$

Answer 2

Answer:

$4^{-3}=2^{-6}\: (base \:2)$

Step-by-step explanation:

$\begin{gathered}4^{-3}\\=\left(2^{2}\right)^{-3}\\=2^{2\times (-3)}\end{gathered}4−3$

$By \: Exponential \: Law:$:

$(am)n=amn$

$=2^{-6}\: (base \:2)$

Therefore,

$4−3=2−6(base2)$

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