Question

$\bf{QuEsTiOn : }$

23 people had lunch in a hotel and the rate per lunch is the same for all. if it costs rs 3105 in total, how much will it cost for 60 people to have lunch in the same hotel at the same rate ?


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Answer 1

Answer:

₹1800

Step-by-step explanation:

total no. of people =23

total cost = ₹3105

cost per people = ₹135

cost per 60 people =135x60 =₹8100

Answer 2

Given Question

23 people had lunch in a hotel and the rate per lunch is the same for all. if it costs Rs 3105 in total, how much will it cost for 60 people to have lunch in the same hotel at the same rate?

$\large\underline{\sf{Solution-}}$

Given that,

23 people had lunch in a hotel and the rate per lunch is the same for all. It costs Rs 3105 in total.

Let assume that

Cost of lunch, if 60 people to have lunch in the same hotel at the same rate be Rs x

We know

Direct Variation :- A variation in two variables x and y is said to be direct variation iff, if there is increase in x, so there is increase in y or if there is decrease in x, so there is decrease in y.

Now, Here,

➢ More people, so more expenditure on Lunch.

➢ So, it means there is a direct variation.

$\begin{gathered}\boxed{\begin{array}{c|c|c} \bf & \bf & \bf \\ \frac{\qquad}{} & \frac{\qquad}{}\frac{\qquad}{} & \frac{\qquad}{} &\\ \sf Number \: of \: Persons & \sf 23 & \sf 60 \\ \\ \sf Cost \: of \: Lunch & \sf 3105 & \sf x\\ \end{array}} \\ \end{gathered}$

So, by using Definition of Direct variation,

$\rm :\longmapsto\:\dfrac{23}{3105} = \dfrac{60}{x}$

$\rm :\longmapsto\:x = \dfrac{60 \times 3105}{23}$

$\rm :\longmapsto\:x = \dfrac{60 \times \: \cancel{3105} \: \: 135}{ \cancel{23}}$

$\rm :\longmapsto\:x = 60 \times 135$

$\rm\implies \:\boxed{\tt{ \: \: x \: \: = \: \: 8100 \: \: }}$

So, Cost of Lunch for 60 people is Rs 8100