Physics, asked by Anonymous, 21 days ago

\bf\; Question \;❓
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A hollow spherical object weighs 25 gm in air. Its material density is 5gm/c.c. If it .weighs 15gm in water, find the volume of the hollow space in it.​
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Answers

Answered by XxsoumyaxX
2

\huge\mathfrak\red{Answer}

We know that,

Density =  \frac{Weight(in \: g)}{Volume(in \: cc)}  \\  = \: W_{1} - W_{2} = loss \: of \: weight \: in \: water = 25 - 15 = 10 \\ volume \: of \: spherical \: object =  \frac{25}{5}  = 5cc \\ volume \: of \: hollow \: space \:  = 10 - 5 = 5cc

Answered by Anonymous
55

Given

  • Weight of Hollow Spherical = 25gm.
  • Material Density = 5,gm/c.c.

To Find

  • Volume of Hollow Space = ?

Solution :

Since the mass of the object is  \text{25g} and it's material density is  \rm{5g/cm^3}

So,

︎⠀⠀ Now Volume of the object =

 \displaystyle \rm{ =  \frac{25 \: g}{5g/cm^3}  =  { \color{brown}5cm {}^{3} }}

When W \tiny{a} and W \tiny{w}

represent the weight of the object in air and water respectively,then weight of water Displaced

 \displaystyle \rm{W \small_{a}} - \:  \:\displaystyle \rm{W \small_{w}}\displaystyle \rm{ =25gwt-  }  \\ \displaystyle \rm{15gwt = 10gwt}

 \star{ \boxed{ \sf{ \color{darkred}{And  \: Mass \:  Of  \: Water  \: Displaced}}}}

 \rm  \dfrac{\displaystyle \rm{W \small_{a}} - \:  \:\displaystyle \rm{W \small_{w}}}{g}=\frac{10gwt}{g} = 10g

Since the Density of Water is\displaystyle \rm{ 1g/cm^3} , The Volume of water Displaced

\displaystyle \rm{ = \dfrac{10g}{ 1g/cm^3}=10cm^3}

Hence,

  • Volume of Hollow Space in the Object =

{ \color{red} \rm{ = 10cm^3 -5cm^3 = 5cm^3}}

{\underline{\underline{\rule{200pt}{5pt}}}}

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