Question

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Three equal charges each having a magnitude of 2.0×10^-6 C are placed at three corners of a right angled triangle of sides 3cm ,4cm and 5cm. Find force on the charge at the right angle corner.



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Answer 1

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Three equal charges each having a magnitude of 2.0×10^-6 C are placed at three corners of a right angled triangle of sides 3cm ,4cm and 5cm. Find force on the charge at the right angle corner.

Answer Is In The Above Pictures!!!

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Answer 2

Answer:-

Steps:-

1. Force between charges at B and A is F(AB) = 9 ×  10^9  × [(2 × 10^-6)^2 ] / (3×10^-2)^2=40 N outwards.

2. Force between B and C isF(BC) =   9 × 10^9  × [(2 × 10^-6)^2 ] / (4×10^-2)^2= 22.5 N outwards.

3. Resultant Force is F(res) = sqrt(F1^2 + F2^2 + 2F1F2cos(90)) as the angle between the forces is 90 degrees.

∴ The resultant force is 45.9 N

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