Question

$\bf {\red {Wrong \: answer \: will \: reported}}$
$\bf {\blue {Correct \: answer \: needed}}\ \textless \ br /\ \textgreater$

$\sf \: { \pink{No \: spam❌❌}}$
​

Answer 1

$\huge{ \mathfrak{ \overline{ \underline{ \underline{ \red{ Answer☻}}}}}}$

QUESTION : -

The consentration of Ag + ion of saturated solution . Ag , Cr04 is 1 . 5 × 10 . 4 m . l l - 1 determine the solubility product of Ag2Cr04 :

SOLUTION : -

Ag 2CrO 4 ⇌2Ag + +CrO 2 / 4

Ag + =1.5×10 −4M

CrO 42− =0.75×10 −4 M( 21 ofAg + )

so ,K ss =(1.5×10 −4 ) 2 ×(0.75××10 −4 )=1.687×10 −12

ANSWER : -

So the answer is 1 . 687 × 10 - 12

Answer 2

$\huge\bf\underline{\green{Answer:-}}$

$\small\bf\underline{\blue{Solution:-}}$

Ag 2CrO 4 ⇌2Ag + +CrO 2 / 4

Ag + =1.5×10 −4M

CrO 42− =0.75×10 −4 M( 21 ofAg + )

so ,K ss =(1.5×10 −4 ) 2 ×(0.75××10 −4 )=1.687×10 −12

$\huge\bf\boxed{\green{Answer:-}}$

So the answer is 1 . 687 × 10 - 12