Question

$\bf \underline{✭Question:-}$
Prove that 3 + √7 is irrational number.

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Answer 1

Answer:

Let us assume the opposite, that 3+7 is rational.

Hence 3+7 can be written in the form ba where a and b are co-prime and b=0.

Hence 3+7 is irrational.

Step-by-step explanation:

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Answer 2

Given :

• $\rm \: 3 + \sqrt{7}$

To find :

• Needed to prove an Irrational number .

Solution :

Here,

Let us assume that 3√7 is rational .

Here 3 is rational and √7 is rational .

As we know that

Product of two rational numbers is always rational .

But , √7 is rational, which is continuously repeated .

So, 3√7 is irrational