Question

$\bf\underline{\underline{Question:}}$

A scooter moving at a speed of 10 m/s is stopped by applying brakes which produce a uniform acceleration of -0.5m/s^2 .How much distance will be covered by the scooter before it stops?

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Answer 1

Answer:

$\huge{\underline{\color{teal}{\textsf{\textbf{~~~Answer}}}}}$

$\sf \bf \: given - \\ \star \:u \: = 10m/s \\ \star \: a \: = - 0.5m/ {s}^{2} \\ \star \: v \: = 0 \\ \sf \bf \: by \:using \: 3rd \: law \: of \: motion - \\ {v}^{2} - {u}^{2} = 2as \\ \: = {0}^{2} - ( { - 10}^{2} ) = 2( - 0.5)s \\ {0}^{2} - (100) = 1s \\ - 100 = s \: \\ \sf \: we \: know \: that \: distance \: cant \: be \: in \: negative \: so \\ \bold s = 100$

Answer 2

$\bf\underline{\underline{ansor:}}$

u= 10m/s

v= 0

a= -0.5 m/s^2

s=?

_______________________

v^2=u^2 +2as

(Putting values)

s= 100m

hmm bai.