Math, asked by yahoo25, 9 months ago


 -  \binom{2}{3}  \times  \binom{3}{5}  +  \binom{5}{2}  -  \binom{3}{5}  \times  \binom{1}{6}
write the whole sum ​

Answers

Answered by Aɾꜱɦ
103

Answer:

 =  \geqslant sum \\     =  \geqslant   -  \binom{ 2}{3}   \times  \binom{3}{5}  +  \binom{3}{5}  \times  \binom{1 }{6 }  +  \binom{5}{2}  \\  =  \geqslant  \binom{3}{5}  -  \binom{2}{3}  +  \binom{1}{6}  +  \binom{5}{2} \\  =  \geqslant  \binom{3}{5}   -  \binom{1}{6} +  \binom{5}{2 }   \\  =  \geqslant  \binom{3}{5}  - 2(2) + 1(1) +  \binom{5}{2}  \\   =  \geqslant \binom{3}{5} ( \frac{4}{6} ) +  \binom{5}{2 }  = ( \frac{ - 3}{5}) \times  \frac{5}{6}   \binom{5}{2}  \\  =  \frac{ - 3}{6}  +  \frac{5}{2 }  \\  =  \geqslant 1( - 3) + 3(5) =  \frac{12}{6 }  \\ both \: are \: cut \: and \: answer \: is \:  \\  =  \leqslant 2 \geqslant  =

Answered by Anonymous
2

Answer:

check the attachment ✅❣️✅

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