Question

$\blue{Please}$$\red{Answer }$$\blue{The}$$\red{Question}$


A battery of 6V is connected in series with
resisters of 0.1 ohm, 0.15 ohm,0.2 ohm, 0.25 ohm and 6 ohm. How much current would flow through the 0.3 ohm resistor?
(a) 0.895A
(b) 2.22A
(c) 1A
(d) none of these​

Answer 1

Answer:

$\red{Answer => (d) none of these}$

Explanation:

$\blue{EXPLANATION=>}$

VOLTAGE GIVEN:-

6V

RESISTORS GIVEN:-

R1=0.1ohm. , R2=0.15ohm. , R3=0.2ohm

R4=0.25ohm. , R5=6ohm

resistors in series:-

$= r1 + r2 + r3 + r4 + r5$

$= 0.1 + 0.15 + 0.2 + 0.25 + 6$

$= > 6.7ohm$

formula for current through resistor:-

$i = \frac{v}{r}$

$V=IR \\ \\ </p><p></p><p>I=\dfrac{V}{R} \\ \\ I=RV \\ \\ </p><p></p><p>I=\dfrac{6\ V}{6.7\ \Omega} \\ \\ I=6.7 Ω6 V</p><p></p><p>$

$I = 0.895 A$

hence, D answer is correct

hope it helps you

❤️AR+NAV❤️

Answer 2

$\huge{\underline{\pink{\tt{Answer :}}}}$

$\longrightarrow$ Option (A) 0.895A

$\huge{\underline{\orange{\tt{Given,}}}}$

• A battery of 6V is Connected in series with Resisters of 0.1 ohm , 0.15 ohm , 0.2 ohm , 0.25 ohm and 6 ohm.

$\huge{\underline{\orange{\tt{To\:Find,}}}}$

• The Current flow through the 0.3 ohm Resistor .

$\huge{\underline{\orange{\tt{Solution :}}}}$

$\bigstar$ Firstly, We Know About law of Series Combination of Resistor :

$\longmapsto$ This Law Define that When Resistor Connected in Series then Each Resistor from current Equally or same pass . In Another word this law means  the Current same at very point of Circuit. The Equivalent Resistance is the sum of of Individual Resistor , its simple means The total Resistance of a Number of Resistor in series is Equal to the sum of all Individual Resistance.

$\mapsto \boxed{\red{\mathfrak{R = R_{1} + R_{2} + R_{3} + R..}}}$

Now, Solve this Question with the Help of this law :

$\longrightarrow \sf{Total\:Resistance = 0.1 + 0.15 + 0.2 + 0.25 + 6}$

$\longrightarrow \underline{\boxed{\sf{Total\:Resistance [R] = 6.7\:ohms}}}$

Therefore,

$\implies$ We have Net Resistance of the Circuit is 6.7 ohms so now we have to find the Current flow through the 0.3 ohm resistor .

║From Series Combination Law we learnt that the Current through each and every Resistor is same ║

$\large{\underline{\pink{\tt{According\:to\:the\:Question :}}}}$

$\bigstar$ We know that ohms Laws   :

$\longmapsto$ This Law Define that Electric Current is Proportional to Potential Difference and Inversely Proportional to Resistance. That's simple means When Voltage Increase then Current will be Increase and When Resistance Increase then Current will be Decrease .

$\mapsto \boxed{\sf{Potential\:Difference = Current \times Resistance}}$

Therefore,

$\implies$We have Potential Difference and Resistance so Now Find Current:

$\mapsto \boxed{\sf{Current = \dfrac{Potential\:Difference}{Resistance}}}$

$\mapsto \sf{Current [I] = \dfrac{6\:V}{6.7\: \Omega}}$

$\mapsto \boxed{\sf{Current[I] = 0.895\:A}}$

Hence,

$\implies$ The Current would flow through the 0.3 ohms Resistor will be 0.895 A.

$\rule{200}2$