Question

$\bold{1.}$ A $\textit{n-p-n}$ transistor in a common-emitter mode is used as a simple voltage-amplifier with a collector-current of 4 mA. The terminals of the 8 V battery is connected to the collector through a load resistance $\sf R_L$ and to the base through a resistance $\sf R_B$. The collector-emitter voltage, $\sf V_{CE}$ = 4 V, the base-emitter voltage, $\sf V_{BE}$ = 0.6 V and the current amplification factor $\beta_{dc}$ = 100. Then
a. $\sf R_L$ = 1 kΩ , $\sf R_B$ = 185 kΩ
b. $\sf R_L$ = 2 kΩ = $\sf R_B$
c. $\sf R_L$ = 2 kΩ , $\sf R_B$ = 15 kΩ
d. $\sf R_L$ = 185 kΩ , $\sf R_B$ = 1 kΩ
$\bold{2.}$ The Boolean expression of the output $\textit{y}$ in terms of the input $\textit{A}$ and $\textit{B}$ for the circuit shown in the figure.​

Answer 1

$\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the Electronics and Digital Electronics.

=> Question No-2.) After solving we get as,

y = AB + A'B'

===> Option C.) is correct

=> Ouestion No-1.) After Solving we get as,

Here option A.) is correct.

I found out that, RB = 185 kohms, then automatically it's RL = 1k ohm.

I have Solved all things in the attachment.

Answer 2

The Nobel Prize is not a single prize but five separate prizes that, according to Alfred Nobel's will of 1895, are awarded to ”those who, during the preceding year, have conferred the greatest benefit to humankind.

add 86 + 3 + 8 + 120 - 56

here u got it !!