Question

$\bold{ \color{navy}{ \boxed { \color{yellow}{ \underline{ \color{magenta}{\mathtt{Verify \: whether \: there \: exists \: a \: polynomial:↓}}}}}}}$

$f(x)$ such that $f(f(x))=x^2-x+1$,

Also find $f(0)$.

Show full process.

$\bold { \color{navy}{Correct + Quality \: answers = Brainliest.}} \\ \small \bold \pink {Wrong \: Answer = Your \: 10 \: spamming \: answers \: reported.}$
Thanks.​

Answer 1

You know that

f(f(0))=1,

then

f(1)=f(f(f(0)))=f(0)2−f(0)+1,(∗)

but also

f(f(1))=12−1+1=1,

so

f(1)=f(f(f(1)))=f(1)2−f(1)−1

and you can calculate f(1) from here, and then substitute its value in (∗)

CAN BE FRIEND

Answer 2

Answer:

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