Question

$\bold{Limits\:and\:derivatives}$

$\bold{Solve}$..❤️

Answer 1

Answer:

$\huge{\boxed{\frac{a+1}{b}}}$

Step-by-step explanation:

A class 10 humble boy cannot do limits still trying....

Use  $\:\bf{\frac{sinx}{x} = 1}$

$\mathsf{\lim_{x \to 0} \frac{ax+xcosx}{bsinx}}\\\\\textbf{Take x as common in the numerator :}\\\\\implies \mathsf{\lim_{x \to 0} \frac{x(a+cosx)}{bsinx}}$

$\implies \mathsf{\lim_{x \to 0} \frac{a+cosx}{b}\times(\frac{x}{sinx})}\\\\\implies \mathsf{\lim_{x \to 0} \frac{a+cosx}{b}\div(\frac{sinx}{x})}\\\\\implies \mathsf{\lim_{x \to 0} \frac{a+cosx}{b}\div 1}}$

Note that cos° 0 = 1

$\mathsf{\implies \frac{a+1}{b}}$

Answer 2

Your answer is in pic......