Question

$\bold\pink{† Question}$

Two particles of mass 200 g each are placed at a separation of 10 cm. Assume that the only forces acting on them are due to their gravitational attraction. Find the acceleration of each when they are allowed to move.

Chapter- Gravitation
Class- IX​

Answer 1

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Gravitational Force on each particle

F = Gm1m2/r²

F = 6.67 x 10^-11 x 0.2 x 0.2 /(0.1)²

F = 2.67 x 10^-33 N

Acceleration of first particle = acceleration of second particle

a = F / m

a = 2.67 x 10^-33/0.2

a = 1.33 x 10^-32 m/s²

Answer 2

Answer:

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Explanation:

• For calculating the acceleration of each first we need to calculate the force.

• Note the given data  
• M = 200 g = 0.2 kg
• m = 100 g = 0.1 kg
• r = 10 cm = 0.1 m

• $G = 6.67$ × $10^{-11} \frac{NM^{2} }{kg^{2} }$

• Now find the force using the formula  

• $F = G\frac{Mm}{r^{2} }$

• $F = 1.364 * 10^{-10} N$

Now acceleration of object having mass 200 g = 0.2 kg will be -

$a1 = \frac{F}{M} \\a1 = \frac{1.334 * 10^{-10} }{0.2}$

a1 = 6.67 × $10^{-10} m/s^{2}$

Now acceleration for the object having 100 g = 0.1 kg mass will be

a2 = $\frac{F}{m} \\=> a2 = \frac{1.334 * 10^{-10} }{0.1}$

a2 = 13.34 × $10^{-10} m/s^{2}$