Question

★$\bold{Question:-}$
An object $5 cm$ high forms a virtual image of $1.25 cm$ high, when placed in front of a convex mirror at a distance of $24 cm$. Calculate :-
(i) the position of the image
(ii) the focal length of the convex mirror.

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Answer 1

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GIVEN:-

object height (h) = 5cm

image height (h') = 1.25cm

object distance (u) = -24cm

position of image (v) = ?

focal length (f) = ?

(a) Magnification (M) = (h')/h = (-v)/u

Substituting the known values :-

1.25/5 = -v/(-25)

5(-v) = 1.25(-25)

-5v = -30

v = -30/-5

v = 30/5

v = 6cm

•°• Image is formed 6cm in front of the mirror.

(b) Mirror formula = 1/v + 1/u = 1/f

1/f = 1/6 + 1/(-24)

1/f = 1/6 - 1/24

1/f = (24 - 6)/144

1/f = 18/144

1/f = 9/72

1/f = 1/8

f = 8cm

•°• Focal length of mirror is 8cm= 6cm

Hey Kalash

HRU

Answer 2

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Hello!!

Answer is in the attachment

hope it helps

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