Math, asked by Anonymous, 11 months ago

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Answered by Anonymous
16

Question:

Show that one and only one out of n, n + 4, n + 8, n + 12 and n + 16 is divisible by 5, where n is any positive integer.

Solution:

We know that ..

a = bq + r

Here .. b = 5 and r = 0, 1, 2, 3, 4.

=> Take b = 5 and r = 0

• n = 5q + 0 = 5q

Divisible by 5

• n + 4 = 5q + 4 + 0 = 5q + 4

Not divisible by 5

• n + 8 = 5q + 8

Not divisible by 5

• n + 12 = 5q + 12

Not divisible by 5

• n + 16 = 5q + 16

Not divisible by 5

______________________________

=> Take b = 5 and r = 1

• n = 5q + 1

Not divisible by 5

• n + 4 = 5q + 4 + 1 = 5q + 5

= 5(q + 1)

Divisible by 5

• n + 8 = 5q + 8 + 1

= 5q + 9

Not divisible by 5

• n + 12 = 5q + 12 + 1

= 5q + 13

Not divisible by 5

• n + 16 = 5q + 16 + 1

= 5q + 17

Not divisible by 5

______________________________

=> Take b = 5 and r = 2

• n = 5q + 2

Not divisible by 5

• n + 4 = 5q + 2 + 4

= 5q + 6

Not divisible by 5

• n + 8 = 5q + 2 + 8 = 5q + 10

= 5(q + 2)

Divisible by 5

• n + 12 = 5q + 2 + 12

= 5q + 14

Not divisible by 5

• n + 16 = 5q + 2 + 16

= 5q + 18

Not divisible by 5

____________________________

=> Take b = 5 and r = 3

• n = 5q + 3

Not divisible by 5

• n + 4 = 5q + 3 + 4

= 5q + 7

Not divisible by 5

• n + 8 = 5q + 3 + 8

= 5q + 11

Not divisible by 5

• n + 12 = 5q + 3 + 12 = 5q + 15

= 5(q + 3)

Divisible by 5

• n + 16 = 5q + 3 + 16

= 5q + 19

Not divisible by 5

_____________________________

=> Take b = 5 and r = 4

• n = 5q + 4

Not divisible by 5

• n + 4 = 5q + 4 + 4

= 5q + 8

Not divisible by 5

• n + 8 = 5q + 4 + 8

= 5q + 12

Not divisible by 5

• n + 12 = 5q + 4 + 12

= 5q + 16

Not divisible by 5

• n + 16 = 5q + 4 + 16 = 5q + 20

= 5(q + 4)

Divisible by 5

____________________________

So, only one out of n, n + 4, n + 8, n + 12 and n + 16 is divisible by 5.

____ [ HENCE PROVED]

_____________________________

Answered by Anonymous
5

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