Question

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➺the amount of money in the account every year when rupees 10,000 deposit at compound interest at 8% per annum by arithmetic progression?​

Answer 1

Answer:

Original Amount = Rs. 10,000

Interest earned in first year = 10,000 × 8%

= 10, 000 x 8/100

= Rs 800

Total amount outstanding after one year

= Rs 10000 + 800

= Rs 10800

Now, interest earned in 2nd year = 10800 x 8/100 = Rs. 864

Total amount outstanding after 2nd year

= Rs10800 + 864

= Rs 11664

Interest earned in 3rd year = 11664 x 8/100

= Rs 933.12

Total amount outstanding after 3rd year

= Rs 11664 + 933.12

= Rs 12597.12

Therefore, the series is

10800, 11664, 12597.12,… Difference between second and first term = 11664 – 10800

= 864

Difference between third and second term = 12597.12 – 11664

= 933.12

Since the difference is not same Therefore, it doesn’t form an AP .

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