Chemistry, asked by ItzShizuka50, 9 days ago


\bold \red{QUESTION \:  1}
Calculate the amount of oxygen gas and potassium chloride formed during the decomposition of 49 g of potassium chlorate.
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 \bold \red{QUESTION \: 2}
Calculate the amount of calcium sulphate obtained by dissolving 112g of calcium oxide (quicklime) in dilute sulphuric acid.

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Answers

Answered by IIXxSavageSoulxXII
39

\large{\underline{\underline{\color{orange}{\boxed{\colorbox{black}{✎Answer 1-:᭄}}}}}} 

\bold{Ans}

= 19.2 g of oxygen

Calculations for grams of potassium chloride:

\bold{Solution}

Decomposition of potassium chlorate takes place as:

2KCLO³⟹2KCL+3O²

Molar mass of potassium chlorate is 122.55 gram per mol.

molar mass of oxygen is 32 gram per mol and molar mass of potassium chloride is 74.55 gram per mol.

Now we can calculate the grams of both the products using dimensional analysis as:

calculations for grams of oxygen:

49gkcio {}^{3} ( \frac{1molkcio {}^{3} }{122.55gkcio  {}^{3}  )} ( \frac{3molo {}^{3} }{2molkcio {}^{3} )} ( \frac{32go {}^{2} }{1molo {}^{2} )}

= 19.2 g of oxygen

Calculations for grams of potassium chloride:

49gkcio {}^{3} ( \frac{1molkcio {}^{3} }{122.55gkcio  {}^{3}  )} ( \frac{3molo {}^{3} }{2molkcio {}^{3} )} ( \frac{32go {}^{2} }{1molo {}^{2} )}

=29.8g KCI

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\large{\underline{\underline{\color{orange}{\boxed{\colorbox{black}{✎Answer 2-:᭄}}}}}} 

\bold{Ans}

122g CaSO4

\bold{Solution}

CaO+H2SO4 = CaSO4 + H20

1vol. 1vol. 1vol. 1vol.

112g.\:\:\:\:?

1vol CaI reacts to form 1vol CaSO4

112g CaO reacts to form (112x1)g CaSO4

=> 112g CaSO4

Answered by kartik597652
0

Ans 1

= 19.2 g of oxygen

Calculations for grams of potassium chloride:

Decomposition of potassium chlorate takes place as:

2KCLO³⟹2KCL+3O²

Molar mass of potassium chlorate is 122.55 gram per mol.

molar mass of oxygen is 32 gram per mol and molar mass of potassium chloride is 74.55 gram per mol.

Now we can calculate the grams of both the products using dimensional analysis as:

calculations for grams of oxygen:

= 19.2 g of oxygen

Calculations for grams of potassium chloride:

=29.8g KCI

Ans2

122g CaSO4

122g CaSO4CaO+H2SO4 = CaSO4 + H20

1vol. 1vol. 1vol. 1vol.

112g.\:\:\:\: ?

1vol CaI reacts to form 1vol CaSO4

112g CaO reacts to form (112x1)g CaSO4

=> 112g CaSO4

Hope it helps you...

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