Question

$\bold\red{Question:}$
A electric heater consumes an energy of 230J with the power of 46W. How much time did the heater take in running condition ?​

Answer 1

Given :

Energy consumed by heater = 230J

Magnitude of power = 46W

To Find :

Time taken by heater in running condition.

Solution :

★ Power is defined as the ratio of energy transferred to electrical instrument per unit time.

• It is a scalar quantity having only magnitude.
• Power is measured in watts (W)

$\dashrightarrow\:\underline{\boxed{\bf{\red{Power=\dfrac{Energy}{Time}}}}}$

• One watt is one joule of energy transferred in one second.

By substituting the given values;

→ P = E / t

→ 46 = 230/t

→ t = 230/46

→ t = 5 s

Answer 2

Explanation:

Power P = Energy consumed / Time

t = E/P = 230/46 = 5 sec