Question

$\bold\red{† Question}$

A road roller 4 m wide and with a diameter of 3.5 m makes 4 revolutions in 1 minute. How much time will it take to roll over an area of 6160 m²?
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Answer 1

Area in one revolution =2πr×width=2π(23.5)×4

                                                                  =722×1035×4=44m2

No. of revolution required to roll area of 6160 m2 

=6160/44

=140

Time required:

=140/4

=35min

Answer 2

Answer:

Area in one revolution =2πr×width=2π(

Area in one revolution =2πr×width=2π( 2

Area in one revolution =2πr×width=2π( 23.5

Area in one revolution =2πr×width=2π( 23.5

Area in one revolution =2πr×width=2π( 23.5 )×4

Area in one revolution =2πr×width=2π( 23.5 )×4 =

Area in one revolution =2πr×width=2π( 23.5 )×4 = 7

Area in one revolution =2πr×width=2π( 23.5 )×4 = 722

Area in one revolution =2πr×width=2π( 23.5 )×4 = 722

Area in one revolution =2πr×width=2π( 23.5 )×4 = 722 ×

Area in one revolution =2πr×width=2π( 23.5 )×4 = 722 × 10

Area in one revolution =2πr×width=2π( 23.5 )×4 = 722 × 1035

Area in one revolution =2πr×width=2π( 23.5 )×4 = 722 × 1035

Area in one revolution =2πr×width=2π( 23.5 )×4 = 722 × 1035 ×4=44m

Area in one revolution =2πr×width=2π( 23.5 )×4 = 722 × 1035 ×4=44m 2

Area in one revolution =2πr×width=2π( 23.5 )×4 = 722 × 1035 ×4=44m 2

Area in one revolution =2πr×width=2π( 23.5 )×4 = 722 × 1035 ×4=44m 2 No. of revolution required to roll area of 6160 m

Area in one revolution =2πr×width=2π( 23.5 )×4 = 722 × 1035 ×4=44m 2 No. of revolution required to roll area of 6160 m 2

Area in one revolution =2πr×width=2π( 23.5 )×4 = 722 × 1035 ×4=44m 2 No. of revolution required to roll area of 6160 m 2 =

Area in one revolution =2πr×width=2π( 23.5 )×4 = 722 × 1035 ×4=44m 2 No. of revolution required to roll area of 6160 m 2 = 44

Area in one revolution =2πr×width=2π( 23.5 )×4 = 722 × 1035 ×4=44m 2 No. of revolution required to roll area of 6160 m 2 = 446160

Area in one revolution =2πr×width=2π( 23.5 )×4 = 722 × 1035 ×4=44m 2 No. of revolution required to roll area of 6160 m 2 = 446160

Area in one revolution =2πr×width=2π( 23.5 )×4 = 722 × 1035 ×4=44m 2 No. of revolution required to roll area of 6160 m 2 = 446160 =140

Area in one revolution =2πr×width=2π( 23.5 )×4 = 722 × 1035 ×4=44m 2 No. of revolution required to roll area of 6160 m 2 = 446160 =140Time required =

Area in one revolution =2πr×width=2π( 23.5 )×4 = 722 × 1035 ×4=44m 2 No. of revolution required to roll area of 6160 m 2 = 446160 =140Time required = 4

Area in one revolution =2πr×width=2π( 23.5 )×4 = 722 × 1035 ×4=44m 2 No. of revolution required to roll area of 6160 m 2 = 446160 =140Time required = 4140

Area in one revolution =2πr×width=2π( 23.5 )×4 = 722 × 1035 ×4=44m 2 No. of revolution required to roll area of 6160 m 2 = 446160 =140Time required = 4140

Area in one revolution =2πr×width=2π( 23.5 )×4 = 722 × 1035 ×4=44m 2 No. of revolution required to roll area of 6160 m 2 = 446160 =140Time required = 4140 =35min