Question

$\bold\red{QUESTION : }$
What is the force of gravity acting on a point of mass of 1 kg released from the height of 1 m from the surface of the earth; the radius of earth is equal to 6.4 x 10 to the power 6 metre of 8 is equal to 6 x 10 to the power 24 kg?

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Answer 1

Given :

▪ Mass of particle = 1kg

▪ Height from ground = 1m

▪ Radius of earth = 6400km

▪ Mass of earth = 6×10$^{24}$kg

To Find :

▪ Gravitational force acting on the partical.

Formula :

✴ Gravitational force :

$\bigstar\:\underline{\boxed{\bf{\red{F=\dfrac{GMm}{r^2}=mg}}}}$

• G = gravitational constant
• M = mass of earth
• m = mass of the body
• r = distance between the bodies
• g = acceleration due to gravity

Calculation :

✴ Distance between centre of the earth and particle (r) = 6400km+1m ≈ 6400km

$\dashrightarrow\tt\:F=\dfrac{GMm}{r^2}\\ \\ \dashrightarrow\tt\:F=\dfrac{(6.67\times 10^{-11})\times (6\times 10^{24})\times (1)}{(6400\times 10^{3})^2}\\ \\ \dashrightarrow\tt\:F=9.8\times 1\\ \\ \dashrightarrow\underline{\boxed{\bf{\blue{F=9.8N}}}}\:\orange{\bigstar}$

Answer 2

★ QUESTION :

What is the force of gravity acting on a point of mass of 1kg released from the height of 1m from the surface of the earth ; the radius of the earth is equals to 6.4 × 10 to the power 6 metre of 8 is equal to 6 × 10 to the power 24 kg ?

GIVEN :

• Mass on which gravity is acting (point of the given mass particle) = 1 kg

• Released from the height on the surface (Ground) = 1 m

• Radius of the Earth = 6400 km

• The mass of the Earth = 6 × 10^24 kg

TO FIND :

• Gravitational force acting upon it = ?

STEP - BY - STEP EXPLAINATION :

➠ Now here, we will apply the Formula for finding 'F'

⟹ F = GMm / r² = mg

After substituting the values, as per the given Formulae →

➠ F = GMm / r^2 = mg

➠ F = ( 6.64 × 10 ^-11 ) × ( 6×10^24 ) × (1) / (6400 × 10^3 ) ^2 = 9.8 × 1 = ( 9.8n )

Therefore, we got here the value of 'Force' = 9.8n