Math, asked by ItzCutePrince1946, 5 hours ago

 { \bold{ \sf{ Find \: using \: distributivity.}}}

 \sf(i) \bigg \{ \dfrac{7}{5} \times \bigg \lgroup \dfrac{ - 3}{12}\bigg \rgroup\bigg\} + \bigg \{ \dfrac{7}{5} \times\dfrac{5}{12} \bigg \}
 \\

 \sf(ii) \bigg \{ \dfrac{9}{16} \times \dfrac{ 4}{12}\bigg\} + \bigg \{ \dfrac{9}{16} \times\dfrac{ - 3}{ \: \: 9} \bigg \}
 \\ \\
 \sf \divideontimes \: {Don't \: dare \: to \: Spam \: !!}
 \sf \divideontimes \:{Give \: Quality \: Answer }

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Answers

Answered by King412
135

 \\  \red{ \bigstar  \: \sf \large \bold{ \underline{Solution :- }}} \\

 \\ \green {\sf(i) \:  \:  \:  \bigg \{ \dfrac{7}{5} \times \bigg \lgroup \dfrac{ - 3}{12}\bigg \rgroup\bigg\} + \bigg \{ \dfrac{7}{5} \times\dfrac{5}{12} \bigg \}}\\

 \\  \sf \:  \:  \:  \implies \:  \frac{7}{5}  \times  \bigg( \frac{ - 3}{12}  +  \frac{5}{12}  \bigg) \\

 \\  \sf \:  \:  \:  \implies \:  \frac{7}{5}  \times    \bigg\{ \frac{( - 3 + 5)}{12}  \bigg \}  \\

 \\  \sf \:  \:  \:  \implies \:  \frac{7}{5}  \times     \frac{2}{12}   \\

 \\  \sf \:  \:  \:  \implies \:   \frac{14}{60}   \\

 \\  \sf \:  \:  \:   \frak{\blue {\implies \:   \frac{2}{30} }}  \\

 \\ \green{ \sf(ii)  \:  \: \bigg \{ \dfrac{9}{16} \times \dfrac{ 4}{12}\bigg\} + \bigg \{ \dfrac{9}{16} \times\dfrac{ - 3}{ \: \: 9} \bigg \} }\\

 \\  \sf \:  \:  \: \:  \:   \implies \:  \: \dfrac{9}{16}  \times  \bigg \{ \dfrac{4}{12}  +  \bigg(\dfrac{ - 3}{ \: \: 9} \bigg)  \bigg \} \\

 \\  \sf \:  \:  \: \:  \:   \implies \:  \: \dfrac{9}{16}  \times  \bigg( \dfrac{36}{108}  + \dfrac{ - 36}{ 108} \bigg)  \\

 \\  \sf \:  \:  \: \:  \:   \implies \:  \: \dfrac{9}{16}  \times  \bigg( \dfrac{0}{108}   \bigg)  \\

 \\  \sf \:  \:  \: \:  \:   \implies \:  \: \dfrac{9}{16}  \times  0  \\

 \\  \sf \blue{ \:  \:  \: \:  \:   \implies \:   0 } \\

Answered by IIkuhuII
2

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