Question

$\bold{Solve:-} \\ \\ \frac{5}{7} + \frac{3}{7} \times \frac{14}{24} = x \\ \\ \bold{then \: x = ?}$
solve it with proper explanation please

Thanks:)​

Answer 1

${\huge{\underline{\large{\mathbb{\green{VERIFIED \: ANSWER}}}}}}$

$\frac{5}{7} + \frac{3}{7} = \frac{5 + 3}{7} = \frac{8}{7} \\ \frac{8}{7} \times \frac{14}{24} = \frac{8 \times 14}{7 \times 24} \\ = \frac{112}{168} \\ = \frac{56}{84} = \frac{28}{42} \\ = \frac{14}{24} = \frac{2}{3}$

Answer 2

$\large\bold{\underline{\underline{Given:-}}}$

$\frac{5}{7} + \frac{3}{7} \times \frac{14}{24} = x$

$\large\bold{\underline{\underline{To\:find:-}}}$

The value of $x$.

$\large\bold{\underline{\underline{Solution:-}}}$

$↬ \frac{5}{7} + \frac{3}{7} \times \frac{14}{24} = x$

$↬ \frac{5}{7} + \frac{3}{24} \times \frac{14}{7} = x$

$↬ \frac{5}{7} + \frac{1}{8} \times \frac{2}{1} = x$

$↬ \frac{5}{7} + \frac{2}{8} = x$

$↬ \frac{5}{7} + \frac{1}{4} = x$

Since the denominators are unequal, we can't simply it.

And so we take the L. C. M. for the denominators.

The L. C M. of $7$ and $4$ is $28$.

Now,

$↬ \frac{5 \times 4}{7 \times 4} + \frac{1 \times 7}{4 \times 7} = x$

$↬ \frac{20}{28} + \frac{7}{28} = x$

$↬ \frac{20 + 7}{28} = x$

$↬ \frac{27}{28} = x$

Therefore, the value of $x$ is $\boxed{ \frac{27}{28} }$.

$\sf\red{Hope\:it\:helps.}$