Question

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A cyclist starts from the centre O of a circular park of radius 1 km reaches the edge P of the park, then cycles along the circumference and returns to the centre along QO as shown in figure. If the round trip takes 10 min, what is the (a) net displacement (b) average speed of the cyclist?
(in metre and kilometre per hour)​

Answer 1

${\tt{\large{\boxed{\orange{displacement \: = 0 m}}}}}$

${\tt{\large{\boxed{\green{Average \: speed \: = \: 21.4 \: km/h \: }}}}}$

Answer 2

$\huge\underline\mathfrak\purple{Answer:}$

(a) NET DISPLACEMENT

-->Displacement is given by the minimum distance Between the initial and final positions of a body.In the given case,the cyclists comes to the starting point after cycling for 10 minutes. Hence, his net Displacement is zero.

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(b) Average speed of the cyclist?

--> Average of velocity is is given by relation:

Average=Velocity

Net Displacement/ Total Time

Since, the net Displacement of the cyclist is zero,his average velocity will also be zero.

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Since the initial position coincides with the final position. So, the net displacement of the cyclist = zero

Since the initial position coincides with the final position. So, the net displacement of the cyclist = zero

Average speed of the cyclist =

Total time taken

Total distance travelled

= OP+PQ+QO / 10 km min^−1

= π+4 /20 ×60kmh^−1

=21.4kmh−1

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